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Dennis and Carmen are standing on the edge of a cliff. Dennis throws a basketball vertically upward, and at the same time Carmen throws a basketball vertically downward with the same initial speed. You are standing below the cliff observing this strange behavior. Whose ball is moving fastest when it hits the ground?

v^2 = v0^2 -2gΔy

in the same speed cause when Dennis basketball back to the initial position "`the throwing position" it will back with the same initial speed with different direction "the same direction as Carmen" so it's the same but it'll take Dennis basketball more time

Dennis

v0 is +

v^2 =+v0^2 -2gΔy

Carmen

v0 is -

v^2 =-v0^2 -2gΔy

-----

g =-9.8 for both

Δy is the same for both

so

Dennis v^2 =+v0^2

Carmen v^2 =-v0^2

add them

v^2+v^2 =0

v^2 =-v^2

please tell me if that's right if not how it can be solve

thank you

## Homework Statement

Dennis and Carmen are standing on the edge of a cliff. Dennis throws a basketball vertically upward, and at the same time Carmen throws a basketball vertically downward with the same initial speed. You are standing below the cliff observing this strange behavior. Whose ball is moving fastest when it hits the ground?

## Homework Equations

v^2 = v0^2 -2gΔy

## The Attempt at a Solution

in the same speed cause when Dennis basketball back to the initial position "`the throwing position" it will back with the same initial speed with different direction "the same direction as Carmen" so it's the same but it'll take Dennis basketball more time

Dennis

v0 is +

v^2 =+v0^2 -2gΔy

Carmen

v0 is -

v^2 =-v0^2 -2gΔy

-----

g =-9.8 for both

Δy is the same for both

so

Dennis v^2 =+v0^2

Carmen v^2 =-v0^2

add them

v^2+v^2 =0

v^2 =-v^2

please tell me if that's right if not how it can be solve

thank you