Density of holes in valence band

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When electrons transition from the valence band (VB) to the conduction band (CB), each electron that leaves creates a corresponding hole in the VB. Therefore, if 2.5 electrons per cubic centimeter migrate from the VB to the CB, the density of remaining holes will also be 2.5 holes per cubic centimeter. This relationship holds true regardless of the effective mass of the electrons in the crystal, as the number of holes is directly tied to the number of electrons that leave the VB. The effective mass of electrons and holes does not influence their numerical density; one electron always results in one hole.
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When electrons leave the valence band and jump over the gap to the conduction band, what is the density of the remaining holes?

If 2.5 electrons/cm^3 leave the VB to the CB, will the density of remaining holes be 2.5 electrons/cm^3?

To me it is logical, but I am wondering if mass of electron can change it. In crystal electron has mass mn*, and in CB, that mass is m0.
 
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1 electron always leaves one hole. If you did not have holes before and 2.5 electrons/cm^3 migrate, then you'll have 2.5 holes/cm^3. The effective mass of electrons and holes does not matter for their number.
 
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