a. Use source transformations to find the voltage V0 in the circuit (green).
b. Find the power developed by the 250V voltage source
c. Find the power developed by the 8A current source
V = IR
voltage division: v = (R / total series r)(v in)
current division: i = (other resistance / math. sum of parallel r)(i in)
P = IV
P = (I^2)(R)
current to voltage, resistor moves up but value stays the same, and voltage replacing current source = (coefficient of resistor)*(coefficient of current source)
a current source in parallel with a resistor or
a voltage source in series with a resistor
The Attempt at a Solution
I think I sort of get the basic idea behind source transformation, but it seems more complicated for this problem. The voltage source is not in series with a resistor and vice versa for the current source.
I think I can / am supposed to do source transformation with the 8A and 125Ω to get this:
not sure if the 125Ω is supposed to be on the bottom though. Any tips?
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