Dependent motion problem with ropes

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The discussion revolves around solving a dependent motion problem involving ropes, where the user is struggling with two unknowns, A and C, and is unsure how to eliminate B from their equations. Participants suggest focusing on the dependencies between length changes and recommend rearranging the equation L = SA - SB + 2SC to isolate SA. They clarify that taking the derivative will help eliminate constants like SB and L, simplifying the problem. The conversation emphasizes the importance of understanding calculus concepts, particularly derivatives, in resolving the issue. Ultimately, the user gains clarity on how to approach their problem.
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Homework Statement


I attached the problem with my attempt.

The problem I have is that I have two unknowns. I think my set up is wrong. Does anyone know where to put the datum/set up this question?

Thanks!
 

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theBEAST said:

Homework Statement


I attached the problem with my attempt.

The problem I have is that I have two unknowns. I think my set up is wrong. Does anyone know where to put the datum/set up this question?

Thanks!

What are your two unknowns? Remember, you're looking for dependencies between certain length changes.
 
gneill said:
What are your two unknowns? Remember, you're looking for dependencies between certain length changes.

I know it's A and C but I don't know how to get rid of B :S
 
theBEAST said:
I know it's A and C but I don't know how to get rid of B :S

Here's your drawing with the distances labeled.

attachment.php?attachmentid=44622&stc=1&d=1330662443.gif


Your equation is:

L = SA - SB + 2SC

What you're looking for is the rate of change of SA with respect to a rate of change of SC. So rearrange your formula to have SA on the left and the rest on the right. Now, are you familiar with calculus (derivatives)?
 

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gneill said:
Here's your drawing with the distances labeled.

attachment.php?attachmentid=44622&stc=1&d=1330662443.gif


Your equation is:

L = SA - SB + 2SC

What you're looking for is the rate of change of SA with respect to a rate of change of SC. So rearrange your formula to have SA on the left and the rest on the right. Now, are you familiar with calculus (derivatives)?

Oh... I see, so if you take the derivative Sb and L are eliminated since they are constant?
 
theBEAST said:
Oh... I see, so if you take the derivative Sb and L are eliminated since they are constant?

Yup.
 
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