Derivation of moment of inertia of a solid sphere

AI Thread Summary
The discussion focuses on the derivation of the moment of inertia for a solid sphere, specifically addressing the formula I=2/5 mR^2. The user initially attempts to use spherical shells for the derivation but encounters an issue, resulting in the incorrect value of (3/5)mR^2. Key insights reveal that when using shells, not all mass is at the same distance from the axis of rotation, which affects the calculation. The conversation emphasizes the importance of correctly accounting for the distribution of mass in the shell during the derivation. Ultimately, the user recognizes the need to adjust their approach to achieve the correct result.
joe5185
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Homework Statement


I need to know why my derivation does not work. I am attempting to derive I=2/5 mR^2

Homework Equations


I have seen people derive it using disks but my question is why do the shells not work? Where in my set up did I go wrong? Thanks

The Attempt at a Solution


I am attempting to use shells to do this.
integral(r^2dm)=I
Ro=p=m/v so pdv=dm
dv=4(pi)r^2dr
moment of inertia (I) =definite integral from r=0 to r=R (4p(pi)r^4dr)

When I solve this integral it becomes (3/5)mR^2 and not (2/5) mR^2
 
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Hello, and welcome to PF!

joe5185 said:
I am attempting to use shells to do this.
integral(r^2dm)=I
What is the moment of inertia of a single thin shell of mass dm and radius r? (Hint: It is not r2dm)
 
TSny said:
Hello, and welcome to PF!What is the moment of inertia of a single thin shell of mass dm and radius r? (Hint: It is not r2dm)
Well in general moment of inertia R^2dm and I am using the thin shells to eventually make up the entire volume so I can sub out for dm in terms of r
 
If all the mass in the element dm is at the same distance r from the axis of rotation, then the moment of inertia about that axis will be r2 dm. For a spherical shell, is all of the mass in the shell at the same distance from the axis?
 
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oh I see. thank you
 
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