Derivation of velocity dispersion from virial theorem?

AI Thread Summary
The discussion focuses on deriving velocity dispersion from the virial theorem, specifically the relationship between kinetic energy (K) and potential energy (U). The user starts with the equation 2K + U = 0 and attempts to express K and U in terms of mass and gravitational parameters. Confusion arises regarding the negative value for velocity squared and the significance of a factor of 2 in the derivation. The correct relationship is clarified as sigma^2 ~ GM/R, emphasizing the importance of the negative sign in gravitational potential energy. The thread highlights the need for careful consideration of signs and factors in the application of the virial theorem.
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Derivation of velocity dispersion from virial theorem??

Hey,

Im probably being a bit dim here but could anyone help me derive the velocity dispersion from the virial theorem. I've got 2K+U=0, K/m~sigma^2 and U/m~GM/R.

From rearranging I get a negative velocity^2? Or maybe its the gravitational force that's negative. Oh and a factor of 2. Is that just ignored??

My notes say the answer is sigma^2~GM/R

Just a bit confused, anyone got any clues?
 
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The virial theorem says that 2T - |U| = 0, where U = -GM/R (the negative sign being important, since gravity is an attractive force).

2T = |U|
 
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