donjt81
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I did this problem but wasnt sure if I did it right. Can anyone check it and see if my approach is correct?
here is the question:
The position of a moving body is given by s = f(t) = t^2 + 24t -1 for 0 <= t <= 8 where s is measured in meters and t in sec. Find the body's displacement for the time interval t = 3 to the time when the velocity is 34 m/s.
here is what i did:
s' = velocity = 2t + 24
34 = 2t + 24
t = 5
so the time interval is 3 <= t <= 5
t + delta t = 5
t = 3
displacement = f(t + delta t) - f(t)
= (5^2 + 24*5 - 1) - (3^2 + 24*3 - 1)
= 144 - 80
= 64 meters
I am wondering if this is correct. I wonder why they put the interval 0 <= t <= 8 ... maybe to throw us off. i don't know...
thanks in advance
here is the question:
The position of a moving body is given by s = f(t) = t^2 + 24t -1 for 0 <= t <= 8 where s is measured in meters and t in sec. Find the body's displacement for the time interval t = 3 to the time when the velocity is 34 m/s.
here is what i did:
s' = velocity = 2t + 24
34 = 2t + 24
t = 5
so the time interval is 3 <= t <= 5
t + delta t = 5
t = 3
displacement = f(t + delta t) - f(t)
= (5^2 + 24*5 - 1) - (3^2 + 24*3 - 1)
= 144 - 80
= 64 meters
I am wondering if this is correct. I wonder why they put the interval 0 <= t <= 8 ... maybe to throw us off. i don't know...
thanks in advance