Derivative as a rate if change - is this correct?

donjt81
Messages
70
Reaction score
0
I did this problem but wasnt sure if I did it right. Can anyone check it and see if my approach is correct?

here is the question:
The position of a moving body is given by s = f(t) = t^2 + 24t -1 for 0 <= t <= 8 where s is measured in meters and t in sec. Find the body's displacement for the time interval t = 3 to the time when the velocity is 34 m/s.

here is what i did:
s' = velocity = 2t + 24
34 = 2t + 24
t = 5

so the time interval is 3 <= t <= 5
t + delta t = 5
t = 3

displacement = f(t + delta t) - f(t)
= (5^2 + 24*5 - 1) - (3^2 + 24*3 - 1)
= 144 - 80
= 64 meters

I am wondering if this is correct. I wonder why they put the interval 0 <= t <= 8 ... maybe to throw us off. i don't know...

thanks in advance
 
Physics news on Phys.org
yeah that's correct.
 
thanks a lot!
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top