Derivative Homework: Checking Answers with Step-by-Step Solutions

AI Thread Summary
The discussion focuses on checking homework solutions related to derivatives. A mistake was identified in the second problem where the derivative was incorrectly equated to the original function. The correct expressions for the derivative were clarified, emphasizing the distinction between C'(A) and C'(81). The calculations for the derivative at a specific value were confirmed as accurate. Overall, the majority of the homework was deemed correct, with the exception of the noted error.
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Homework Statement


Can someone check my homework?
http://img10.imageshack.us/img10/9686/48742895.jpg
http://img229.imageshack.us/img229/6981/52780988.jpg
http://img297.imageshack.us/img297/6955/85086758.jpg
http://img11.imageshack.us/img11/1221/86324492.jpg
thx!

Homework Equations





The Attempt at a Solution

 
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In problem 2 you have a mistake.
You have
C = 2sqrt(A*pi) = 2(A*pi)^(1/2) = (A*pi)^(-1/2) *pi

The 2nd and 3rd expressions above are not equal. You have apparently taken the derivative, but you show it as being equal to C. The derivative of C is not equal to C.
 


Mark44 said:
In problem 2 you have a mistake.
You have
C = 2sqrt(A*pi) = 2(A*pi)^(1/2) = (A*pi)^(-1/2) *pi

The 2nd and 3rd expressions above are not equal. You have apparently taken the derivative, but you show it as being equal to C. The derivative of C is not equal to C.

Oh, I forgot to put C'!
Is that the only mistake i got?
 


You got the right answer, but make sure you understand the difference between C'(A) and C'(81)

C'(A) = sqrt(pi/A)
C'(81) = sqrt(pi/81) \approx .1969

Another way to write what you're doing is this:

\frac{\Delta C}{\Delta A} \approx \frac{dC}{dA}
\Rightarrow \Delta C \approx \frac{dC}{dA} \Delta A
\Rightarrow \Delta C \approx \frac{dC}{dA}|_{A = 81} \Delta A
\approx .1969 * 1 = .1969

Everything looks fine for the other problem.
 
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