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Derivative of arcsec(sqrt(x))

  1. Dec 13, 2005 #1
    Hmmm, I dont seem to get it..

    y' of arcsecx is : (1/x * sqrt(x^2 - 1))

    im looking for arcsec(sqrt(x))

    So I get (1/(sqrt(x)sqrt(x-1)) * 1/2sqrt(x))


    Thats not the answer in the book :(

    Help please
     
  2. jcsd
  3. Dec 13, 2005 #2

    Physics Monkey

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    Your answer looks ok, what is the answer the book gives?
     
  4. Dec 13, 2005 #3
    thanks for the reply!

    The answer given is : 1 / (2x * sqrt(x-1))
     
  5. Dec 13, 2005 #4

    Physics Monkey

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    Look closely, your answer is actually the same as the book's.

    Edit: At least I think it is, unless I'm misinterpreting your answer.
     
    Last edited: Dec 13, 2005
  6. Dec 13, 2005 #5
    Hmmm, I dont see it.. and i substitued X by a number, and it gives me 2 different answers
     
  7. Dec 13, 2005 #6

    Physics Monkey

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    Is your answer [tex] \frac{1}{\sqrt{x}\sqrt{x - 1}}\frac{1}{2 \sqrt{x}} [/tex] or something else?
     
  8. Dec 13, 2005 #7
    ya, thats my answer
     
  9. Dec 13, 2005 #8

    Physics Monkey

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    Well, it is the same then. Just combine the two square roots of x to obtain
    [tex] \frac{1}{\sqrt{x}\sqrt{x - 1}}\frac{1}{2 \sqrt{x}} = \frac{1}{2 x \sqrt{x - 1}}.[/tex]
     
  10. Dec 13, 2005 #9
    Ahh!!!! Thanks so much!
     
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