Derivative of arcsec(sqrt(x))

  • Thread starter gr3g1
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  • #1
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Hmmm, I dont seem to get it..

y' of arcsecx is : (1/x * sqrt(x^2 - 1))

im looking for arcsec(sqrt(x))

So I get (1/(sqrt(x)sqrt(x-1)) * 1/2sqrt(x))


Thats not the answer in the book :(

Help please
 

Answers and Replies

  • #2
Physics Monkey
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Your answer looks ok, what is the answer the book gives?
 
  • #3
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thanks for the reply!

The answer given is : 1 / (2x * sqrt(x-1))
 
  • #4
Physics Monkey
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Look closely, your answer is actually the same as the book's.

Edit: At least I think it is, unless I'm misinterpreting your answer.
 
Last edited:
  • #5
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Hmmm, I dont see it.. and i substitued X by a number, and it gives me 2 different answers
 
  • #6
Physics Monkey
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Is your answer [tex] \frac{1}{\sqrt{x}\sqrt{x - 1}}\frac{1}{2 \sqrt{x}} [/tex] or something else?
 
  • #7
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ya, thats my answer
 
  • #8
Physics Monkey
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Well, it is the same then. Just combine the two square roots of x to obtain
[tex] \frac{1}{\sqrt{x}\sqrt{x - 1}}\frac{1}{2 \sqrt{x}} = \frac{1}{2 x \sqrt{x - 1}}.[/tex]
 
  • #9
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Ahh!!!! Thanks so much!
 

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