Derivative of inverse hyperbolic functions

Click For Summary
SUMMARY

The derivative of the inverse hyperbolic function sinh-1(x) can be found using implicit differentiation. By setting y = sinh-1(x), one can express x as sinh(y) and differentiate both sides with respect to y. This method leads to the derivative being expressed in terms of x, specifically as 1/√(x² + 1). This approach clarifies the relationship between the inverse function and its derivative.

PREREQUISITES
  • Understanding of hyperbolic functions, specifically sinh(x) and cosh(x).
  • Knowledge of implicit differentiation techniques.
  • Familiarity with basic calculus concepts, including derivatives.
  • Ability to manipulate algebraic expressions involving square roots.
NEXT STEPS
  • Study the differentiation of other inverse hyperbolic functions, such as cosh-1(x) and tanh-1(x).
  • Learn about the applications of inverse hyperbolic functions in calculus.
  • Explore implicit differentiation in more complex scenarios.
  • Review the properties and graphs of hyperbolic functions for better understanding.
USEFUL FOR

Students studying calculus, particularly those focusing on derivatives of inverse functions, and educators seeking to explain hyperbolic function differentiation.

mvantuyl
Messages
37
Reaction score
0

Homework Statement


I don't understand how to take the derivative of inverse hyperbolic functions such as sinh[tex]^{-1}[/tex](x). I know that the derivative of sinh(x) is cosh(x) but don't know what to do with the inverse.


Homework Equations





The Attempt at a Solution


I'm completely at a loss here. Could somebody point me in the right direction? (I don't necessarily want the answer, just a shove along the path would be wonderful)
 
Physics news on Phys.org
Welcome to PF!

Hi mvantuyl! Welcome to PF! :smile:

Hint: if y = sinh-1x, then write x = sinhy, and then differentiate (and then convert back into x's, of course)! :wink:
 


Thank you! It's so obvious I managed to completely overlook it. :)
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
3
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K