Derivative of P(x) = 0.2 -0.125e^(0.005x) for X=1

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Homework Statement


Derivative of P(x) = 0.2 -0.125e^(0.005x) for X=1
P(x) is the population in Millions and X is the year where 0 = 2000
I have to explain the answer I am getting at the end.

Homework Equations

The Attempt at a Solution


d/dx (0.2 -0.125e^(0.005x))
I find -0.000625*(1,00501)^x // did this with my calculator
-0.000625*(1,00501)^1 = -0.000628

does that simply mean that the population is going down over time?
 
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Welcome to PF,
Great work, just want to point at something, P(x) = 0.2 -0.125*e^(0.005)
It has a something constant - some exponontial, so it will be decreasing so fast over the years,
Hope I've helped,
[Edit: To answer, you have to write down the derevative of P in terms of x, and what should it's sign be to be decreasing ?]
 
masterchiefo said:

Homework Statement


Derivative of P(x) = 0.2 -0.125e^(0.005x) for X=1
P(x) is the population in Millions and X is the year where 0 = 2000
I have to explain the answer I am getting at the end.

Homework Equations

The Attempt at a Solution


d/dx (0.2 -0.125e^(0.005x))
I find -0.000625*(1,00501)^x // did this with my calculator
-0.000625*(1,00501)^1 = -0.000628
No.
I don't know what you entered into your calculator, but it came out wrong. The derivative should involve e raised to the power kx.

I would advise putting your calculator away and doing this by hand. You're more likely to get the right answer.
masterchiefo said:
does that simply mean that the population is going down over time?
 
Mark44 said:
No.
I don't know what you entered into your calculator, but it came out wrong. The derivative should involve e raised to the power kx.

I would advise putting your calculator away and doing this by hand. You're more likely to get the right answer.
Thats because my calculator calculated e^0.005*x = 1.00501^x
 
Noctisdark said:
Welcome to PF,
Great work, just want to point at something, P(x) = 0.2 -0.125*e^(0.005)
It has a something constant - some exponontial, so it will be decreasing so fast over the years,
Hope I've helped,
[Edit: To answer, you have to write down the derevative of P in terms of x, and what should it's sign be to be decreasing ?]
Yeah I wrote down the derevative of P in terms of x and I believe that since its negative the population is decreasing ?
 
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Yepp, great work .
 
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Noctisdark said:
Yepp, great work .
thanks awesome.

This forums makes me like University even more :) I love school & studying :)
 
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masterchiefo said:
Thats because my calculator calculated e^0.005*x = 1.00501^x
Operator error

To make that calculation, you need parentheses, as in e^(.005*x).
 
Noctisdark said:
Yepp, great work .
Please pay closer attention before making comments about the correctness of a poster's work. The OP made a gross error in his first post, which you apparently didn't notice.
 
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Mark44 said:
Operator error

To make that calculation, you need parentheses, as in e^(.005*x).
oh ok thank you very much :)
 
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