Solve e^xy Derivative at (ln.8, .5)

  • Thread starter john.duke10
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In summary, the formula for taking the derivative of e^xy is dy/dx = ye^xy + xe^xy. The point (ln.8, .5) represents the specific coordinates where the derivative of e^xy is being evaluated. To solve for the derivative of e^xy at the point (ln.8, .5), plug in the x and y values into the formula dy/dx = ye^xy + xe^xy and solve for the derivative. The purpose of taking the derivative of e^xy is to find the rate of change of the function at a specific point and to determine the slope of the tangent line at that point. Other mathematical concepts related to taking the derivative of e^xy include the
  • #1
john.duke10
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Homework Statement


e^xy=any number


Homework Equations



you are given a point say (ln.8, .5)
how would u find the derivative at that point?

The Attempt at a Solution

 
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  • #2
That's not grammatical. (e^x)*y or e^(x*y)?? They aren't the same.
 

What is the formula for taking the derivative of e^xy?

The formula for taking the derivative of e^xy is dy/dx = ye^xy + xe^xy.

What does the point (ln.8, .5) represent in this context?

In this context, the point (ln.8, .5) represents the specific coordinates where the derivative of e^xy is being evaluated.

How do you solve for the derivative of e^xy at the point (ln.8, .5)?

To solve for the derivative of e^xy at the point (ln.8, .5), plug in the x and y values into the formula dy/dx = ye^xy + xe^xy and solve for the derivative.

What is the purpose of taking the derivative of e^xy?

The purpose of taking the derivative of e^xy is to find the rate of change of the function at a specific point and to determine the slope of the tangent line at that point.

What other mathematical concepts are related to taking the derivative of e^xy?

Other mathematical concepts related to taking the derivative of e^xy include the chain rule, product rule, and quotient rule. It is also related to the concept of exponential functions and their derivatives.

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