Deriving d = 1/2 a t2: Intro Physics Proof

AI Thread Summary
The discussion focuses on deriving the equation d = 1/2 a t², which relates distance, acceleration, and time. A participant expresses uncertainty in approaching the problem due to a lack of familiarity with physics and mathematics. Another suggests taking the derivative of distance with respect to time to find velocity, indicating a foundational approach to the derivation. The conversation highlights the need for clarity in understanding basic physics concepts. Overall, the thread seeks assistance in comprehending the derivation process for this fundamental equation.
cosmic-barley
Messages
1
Reaction score
0

Homework Statement


Show a derivation of d = 1/2 a t2

Homework Equations


hint: v=a*t

The Attempt at a Solution


I'm not sure how to attempt this. to be perfectly frank I am not well versed in physics/mathematics. If anyone could be of assistance, i would be most grateful.
 
Physics news on Phys.org
take the derivative of d with respect to t and that will give you the velocity.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top