Deriving 'G' from E=mc^2 and Gravitons

AI Thread Summary
The discussion centers on the constant 'G', which represents the gravitational constant in physics, and its relationship to the concept of gravitons, hypothetical particles that mediate gravitational forces. The mathematical expressions provided illustrate how 'G' relates to force, mass, and acceleration, emphasizing the stability of the speed of light (c) in gravitational interactions. The argument suggests that 'G' serves as a mathematical tool to maintain consistency in gravitational equations, similar to how the speed of light is treated in other physics equations. The conversation also touches on the broader implications of these constants in understanding fundamental forces. Overall, the discussion highlights the intricate connections between gravitational forces, mass, and the constants that govern them.
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What does the unit and magnitude of constant 'G' mean, and what is its relation with graviton? ANY OPINION?


Here is how i see it:

E=mc^2
c^2=E/m where E=W=Fr (r stands for radius or distance or ‘s’)
therefore c^2= Fr/m
therefore c^2= c^2----when forces interact the forces hold true the constant c^2 in order to remain stable

therefore Fr/m= Fr/m

Fr/m=mar/m ----where F=ma
Fr/mm=ar/m ----where a=F/m

therefore Fr/mm=Fr/mm

Fr/mm=Fvt/mm ----v=r/t where r=vt
Fr/mm=Frt/tmm ----where v=r/t

therefore Frt/mm=Frt/mm

Frt/mm=Frr/vmm ----where t=r/v
Frtv/mm=Frr/mm ----where v=r/t

therefore Frr/mm=Frr/mm

where F=(Frr/mm)mm/r^2 ----(Frr/mm) is proportionality for example: F=Kq1q2/r^2-electromagnetic force

The "G" (=Frr/mm) is a way of expressing how the constant c is kept true mathematically when forces interact just the way c^2 is a mathematical expression expressing that c should always remain true in order for the matter to remain stable
 
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That don't make any difference.
 
QuantumNet
what doesen't make any difference?
thanks
 
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