Appleton
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If a general conic is
<br /> ax^2+2hxy+by^2+2gx+2fy+c=0<br />
I am told that, if P(p, q) is a point on this conic, then the polar of P(p, q) to this conic is
<br /> apx+h(py+qx)+bgy+g(p+x)+f(q+y)+c=0<br />
How is this derived?
<br /> ax^2+2hxy+by^2+2gx+2fy+c=0<br />
I am told that, if P(p, q) is a point on this conic, then the polar of P(p, q) to this conic is
<br /> apx+h(py+qx)+bgy+g(p+x)+f(q+y)+c=0<br />
How is this derived?