Design an audio power amplifier

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davenn said:
yes that is OK, the reg's in that circuit were just a progression for if a well regulated supply was needed ... feeding IC's for example
Thanks
 
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This amp IC (in the attachment) , is expected to deliver around 8W to an 8ohm load. That means the rms output would be 8v.

1) looking at the circuit, the gain must be decided by the 150k & 4.7k divider, which gives a gain of ~30. (Am I right?)
I learned the headphone jack has a max output of 1v rms. This means the output of the amp would be 15v at half input. This exceeds the figure given by the amp manufacturer. Am I wrong with the gain?

2) What is the use of those diodes going from the output to the supply? Are they a kind of protection? Do I need to incorporate them compulsarily?

Thanks.
 
The amplifier :
 

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PhysicoRaj said:
1) looking at the circuit, the gain must be decided by the 150k & 4.7k divider, which gives a gain of ~30. (Am I right?)
I learned the headphone jack has a max output of 1v rms. This means the output of the amp would be 15v at half input. This exceeds the figure given by the amp manufacturer. Am I wrong with the gain?

so you can adjust those resistor values to give a useable gain
Also I think I mentioned in an earlier post, you should have a volume control in the input for gain adjustment so that you don't overdrive the input to the IC and cause distortion

PhysicoRaj said:
2) What is the use of those diodes going from the output to the supply? Are they a kind of protection? Do I need to incorporate them compulsarily?

these diodes are for the protection of the IC from voltage spikes on the output
Note for a single rail PSU, as you are using, here is a valid connection for them ...

TDA2030.gif


also note, this chip is capable of around 12-14W for a 4 Ohm load and up to 18W for a 8 Ohm loadDave
 
Thanks. I am worried about the output because I have to run my 8ohm speaker at 8w, without knowing what the amp is ousting at the moment.. (can't measure the output on my DMM since it's not a sine). I'll have to play with the volume control and gain, and hope my load won't smoke off.
Is there a way to know the output?
 
PhysicoRaj said:
Is there a way to know the output?

audio wattmeter
oscilloscope
measure the voltage across a known load resistor ( 8 Ohm)Dave
 
PhysicoRaj said:
Is there a way to know the output?
Depends on how accurate you need to be, what response you require, etc. Not sure what your goal is.

For example, you could build a true RMS detector with a threshold comparator and an LED, or add a VU meter, or just detect high output peaks, or whatever.
 
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Thanks! I downloaded a 1kHz sine beep. I'll play it in a loop and check the rms across the load. Then I hope I can work out the gain etc.
 
LOL --- ok, you were just trying to get the gain aprox. correct. I thought you wanted continuous monitoring for some reason.
 
:D well it'd be nice if I had some continuous monitoring, but the only thing I have (and could afford to) is a DMM.
It's enough because I just want to know when the amp is at min/max/optimum, so that I can hook up the speakers at the correct operating point.
 
PhysicoRaj said:
I just want to know when the amp is at min/max/optimum, so that I can hook up the speakers at the correct operating point.

that sounds a really strange statement

Dave
 
davenn said:
that sounds a really strange statement

Dave
I'm not sure if the amp is going to blindly deliver 8w to 8ohms it's a function of input voltage. So to check the limit I'll have to vary both the input (volume control) and the gain, check the output on an 8 Ohm load {not sacrificing my speakers, maybe another old speaker ;)} get it to around 6w undistorted, then connect the speakers. That's what I meant.