Designing a circuit (basic electric circuit analysis)

InvalidID
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Homework Statement

Design a dc circuit utilizing a 15V voltage battery to provide the following node voltages: +10V, +5V, and -5V w.r.t. a circuit ground node. Select your resistors such that the maximum power demand on the battery does not exceed 1mA.

The attempt at a solution

I've designed the attached circuit, but I'm not sure how to find the resistance for each circuit. I know that the total resistance of all four circuits must add up to 225000Ω using the calculations attached.
 

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Perhaps start by marking the ground node and which nodes you intend being 10V, 5V and -5V. Hint: You only need 3 resistors all the same value.
 
InvalidID said:
Homework Statement

Design a dc circuit utilizing a 15V voltage battery to provide the following node voltages: +10V, +5V, and -5V w.r.t. a circuit ground node. Select your resistors such that the maximum power demand on the battery does not exceed 1mA.
mA is not a unit of power; it's a unit of current. Are you sure that the question states that it wants a power limit and not a current limit? Or is it just badly phrased and they really expect a current limit of 1mA? (it would make sense)
The attempt at a solution

I've designed the attached circuit, but I'm not sure how to find the resistance for each circuit. I know that the total resistance of all four circuits must add up to 225000Ω using the calculations attached.
Suppose you set a fixed current value. How many resistors do you think you'd need to provide three potential drops? Should the drops be of different or equal magnitude?
 
CWatters said:
Perhaps start by marking the ground node and which nodes you intend being 10V, 5V and -5V. Hint: You only need 3 resistors all the same value.

Alright. I'm trying that right now.

gneill said:
mA is not a unit of power; it's a unit of current. Are you sure that the question states that it wants a power limit and not a current limit? Or is it just badly phrased and they really expect a current limit of 1mA? (it would make sense)

Hmm... I doubled checked the question and it seems that they used the wrong units. I guess I'll ask the professor or TA. I think they just wrote the wrong units, because that's an easy mistake to make.

gneill said:
How many resistors do you think you'd need to provide three potential drops? Should the drops be of different or equal magnitude?

Resistors cause voltage drops, so for 3 voltage drops, I would need three resistors. Since the increments are in equal value (i.e. -5, 0, 5, 10), then I guess that the resistors need to be all the same value.
 
I think I did it!

One question: how would I make (1) the ground node and still have the other nodes have voltages of: -5V, +5V, and +10V w.r.t. (1)?
 

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InvalidID said:
I think I did it!
Yes, looks fine.
One question: how would I make (1) the ground node and still have the other nodes have voltages of: -5V, +5V, and +10V w.r.t. (1)?
You can't. Making node (1) the reference node would put the other nodes at -5, -10, -15 volts with respect to it.
 
I think I did it!

I think you have the battery the wrong way around.
 
This is how I would draw it.. Note how this layout has the higher voltage nodes at the top of the page and lower voltage/negative voltages at the bottom.
 

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I'm curious. What did you use to draw that circuit?
 
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