Determinant of 4x4 Matrix with Given Value and Variable Columns

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Homework Statement


If a 4x4 matrix A with rows v1, v2, v3 and v4 has determinant detA =-2

then

then det (v1, 9v2+5v3, 5v2+8v3, v4) =___?


Homework Equations





The Attempt at a Solution



Ok, so I think it should be -18 (since 9 x -2). I mean the determinant should not change when adding columns to each other, however multiplying should have an effect, but I am not quite sure what happened to the v3, like do I multiply the determinant by 8, or 5, or none?
 
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I'll give you a sample, det(v1,9*v2+5*v3,v3,v4)=
det(v1,9*v2,v3,v4)+det(v1,5*v3,v2,v5)=
9*det(v1,v2,v3,v4)+5*det(v1,v3,v3,v4). What's that? Now what happens if you put the linear combination in for v3 as well?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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