- #1
Telemachus
- 835
- 30
Hi there. I have found the surface tension for liquid etanol on a given problem. Then the problem says: supposing that the coordination number for etanol is 12, what value does the intermolecular interaction energy has?
I have ##\gamma=21,26355\frac{dyna}{cm}##, gamma is the surface tension that I've found.
The coordination number gives the number of molecules around one molecule in the liquid. I think that because the surface tension happens in the interface, the coordination number in there is 12/2=6.
I also know that ##\gamma=F/2l##, I have this in my notes from class. This is what you get by analysing the virtual work by pushing a thin film a ##\Delta x## distance.
##F\Delta x=2l\Delta x \gamma##
PS: I made a mistake in the title, it's not the determination of intermolecular forces, but intermolecular energy.
I have ##\gamma=21,26355\frac{dyna}{cm}##, gamma is the surface tension that I've found.
The coordination number gives the number of molecules around one molecule in the liquid. I think that because the surface tension happens in the interface, the coordination number in there is 12/2=6.
I also know that ##\gamma=F/2l##, I have this in my notes from class. This is what you get by analysing the virtual work by pushing a thin film a ##\Delta x## distance.
##F\Delta x=2l\Delta x \gamma##
PS: I made a mistake in the title, it's not the determination of intermolecular forces, but intermolecular energy.
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