Determination of iron purity by redox reaction

AI Thread Summary
The discussion revolves around a titration problem involving iron purity, where a sample is titrated with potassium permanganate (KMnO4) to determine the iron content. The user calculated the moles of KMnO4 used in the titration, finding it to be 3x10^-4 moles based on a concentration of 0.02M and a volume of 15 cm³. From the stoichiometry of the reaction, they determined that this corresponds to 1.5x10^-3 moles of iron. The mass of iron calculated from these moles is approximately 0.0838g. Given the original mass of the sample is 3.80g, the expected iron purity is around 88-89%. The user expresses confusion over their calculations and suggests that the 15 mL might refer to the volume of the titrated sample rather than the titrant, indicating potential dilution factors that could affect the results.
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Hi just wondering if you could help, I've stumbled across an example question where the iron purity is meant to be above 80% when

8H+ + 5Fe2+ + MnO4- → 5Fe3+ + Mn2+ + 4H2O

15cm3 is titrated and concentration of potassium permanganate used is 0.02M

So far I have worked out

Number of moles of potassium permanganate=

Concentration x Volume(cm3) = 0.02 x 15 = 3x10-4 moles
1000 1000


From the equation the ratio of moles of potassium permanganate to moles of iron is 1:5

Therefore 3x10-4 x 5= 1.5x10-3 Moles of Iron for sample “A”


Mass of Iron: Molesx Relative atomic mass= 1.5x10-3 x 55.845 = 0.0837675g

The original mass of sample is 3.80g and the iron purity in the answers is around 88-89%

Can anybody help me understand where I've gone wrong?
 
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Sounds to me like 15 mL is volume of titrated sample, not volume of the titrant. I guess there are other details - like dilution of the sample - that can be important.

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http://www.titrations.info
 
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