1. The problem statement, all variables and given/known data The velocity of a particle along s-axis is given as v = 5s^(3/2) , where "s" is in millimeters and v is in millimeters/second. Determine the acceleration when "s" is 2 mm. So I've been having trouble with differential equations, and I think that's where I'm messing up. My classes haven't really covered velocity-position plots, just velocity-time plots and my book is confusing. The answer to the question is 150 mm/s. 2. Relevant equations ∫vdv = ∫a ds 3. The attempt at a solution First I used the equation to try to solve it. ∫(0 to v) vdv = ∫(0 to 2) a ds This gave me (1/2)v^2 = 2a Then I plugged v = 5s^(3/2) into it and got (1/2)(25s^3) = 2a Then I plugged in s = 2 and got 100 = 2a Then I finished solving for a and got a = 50 mm/s, which is incorrect.