Determine current using Kirchoff's Junction/Loop Rule

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SUMMARY

The discussion focuses on applying Kirchhoff's Junction and Loop Rules to determine the currents i1, i2, and i3 in a circuit with resistances R1 = 6 Ω, R2 = 13 Ω, and R3 = 19 Ω, and EMFs Vemf,1 = 10 V and Vemf,2 = 15 V. The equations derived include i1 + 12 = i3 and V1 + I3R3 + I1R1 = 0, leading to the conclusion that summing the equations provides a solvable system for I3. The participant successfully solved for the currents after adjusting their approach to the equations.

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  • Familiarity with Kirchhoff's Junction Rule
  • Basic knowledge of Ohm's Law (V=IR)
  • Ability to manipulate algebraic equations
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Homework Statement



In the circuit shown in the figure, R1 = 6 Ω, R2 = 13 Ω, and R3 = 19 Ω, Vemf,1 = 10 V, and Vemf,2 = 15 V. Using Kirchhoff's Loop and Junction Rules, determine the currents i1, i2, and i3 flowing through R1, R2 and R3, respectively, in the direction indicated in the figure.



Homework Equations



i1 + 12 = 13

V=IR


The Attempt at a Solution



i1 + 12 = i3

V1 + I3R3 + I1R1 = 0

V2 + I2R2 + I3R3 = 0

I1 = (-V1 - I3R3)/R1

I2 = (-V2 - I3R3)/R2

I3 = (-V1 - I1R1)/R3

Does this look right?
 

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The last equation leads you nowhere. Instead, sum the two previous equations, that, together with the first equation, will give you an equation from which you will be able to find I3.
 
Thanks. I was able to solve it.
 

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