Determine Dimensions of Physical Quantities: F, p

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Homework Help Overview

The discussion revolves around determining the dimensions of physical quantities, specifically force (F) and pressure (p), using fundamental equations. The subject area includes dimensional analysis in physics, focusing on the relationships between mass, length, and time.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to express force and pressure in terms of their dimensional units but expresses confusion about the question's requirements. Some participants suggest refining the dimensional expressions and question the correctness of the original poster's calculations.

Discussion Status

Participants are actively engaging with the problem, providing hints and feedback on the dimensional expressions. There is a recognition of errors in the initial attempts, and some guidance has been offered to clarify the dimensional relationships involved.

Contextual Notes

There is a noted lack of clarity regarding the definitions and relationships of the physical quantities, as well as the proper application of dimensional analysis. Participants are encouraged to explore the units of force and pressure further.

you_of_eh
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From the following defining equations, determine the dimensions of the names physical quantities. Use L to represent the dimension length (distance), T to represent time and M to represent mass.

a) force, F: F=ma, (where m is mass and a is acceleration)
b) pressure, p: p=F/A, (where F is a force (see previous question) and A is an area)

-I don't need the answer it's just that I can't even attempt to solve the question as I have no idea what the question is asking for.

a) F=M*d(L/T)/dT ?
b) p=M*d(L/T)/dT/L^2 ?

..that is all that I could come up with.

Thank you for your time.
 
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you_of_eh said:
From the following defining equations, determine the dimensions of the names physical quantities. Use L to represent the dimension length (distance), T to represent time and M to represent mass.

a) force, F: F=ma, (where m is mass and a is acceleration)
b) pressure, p: p=F/A, (where F is a force (see previous question) and A is an area)

-I don't need the answer it's just that I can't even attempt to solve the question as I have no idea what the question is asking for.

a) F=M*d(L/T)/dT ?
b) p=M*d(L/T)/dT/L^2 ?

..that is all that I could come up with.

Thank you for your time.

Welcome to the PF. You are close... For a), just clean up what you have, and leave out the d symbols. The units of a change in length are still length. Does that help?
 
OK yea I get it..

a) F = M(L^3)(T^2)
b) p = ML/T^2
 
you_of_eh said:
OK yea I get it..

a) F = M(L^3)(T^2)
b) p = ML/T^2

Much closer. But you messed up a division in a) (I didn't check b).

Hint -- The unit of force is a Newton. Look up what the sub-units are that make up a N.
 
Well I checked it a couple times..seems correct to me.
 
Try plugging in actual units. M = kg, L = m, T = s

For a) you're saying F = M(L^3)(T^2)

which means, N(Newton) = kg * m3 * s2, and that is close, but not right.

Edit: Also, b) is wrong. Again, p = ML/T^2 is close, but not right.

You're saying, p = kg * m / s2
 
Last edited:

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