Determine its escape velocity in miles/s?

AI Thread Summary
To determine the escape velocity of a space probe launched from a space station 200 miles above Earth, the relevant equations involve gravitational forces and energy conservation. The escape velocity is calculated to be approximately 6.76 miles/s. The discussion emphasizes the need to consider both potential and kinetic energy to find the initial speed required for the probe to escape Earth's gravity. A suggestion is made to convert measurements to metric for easier calculations before converting back to miles. Understanding the conditions for escape is crucial for solving the problem effectively.
Math10
Messages
301
Reaction score
0

Homework Statement


A space probe is to be launched from a space station 200 miles above Earth. Determine its escape velocity in miles/s. Take Earth's radius to be 3960 miles.

Homework Equations


None.

The Attempt at a Solution


m(dv/dt)=-(mgR^2)/(x+R)^2
dv/dt=-(gR^2)/(x+R)^2
Now what?
The answer is 6.76 miles/s.
 
Physics news on Phys.org
Math10 said:

The Attempt at a Solution


m(dv/dt)=-(mgR^2)/(x+R)^2
dv/dt=-(gR^2)/(x+R)^2
Now what?
What is the condition for escape? (hint: what is the potential energy and what is the kinetic energy of the body when it has reached a distance where the Earth's gravity is negligible and the body is just barely moving?). Use the principle of conservation of total energy to determine what its speed must be initially in order to achieve that distance.

Suggestion: I would convert to metric, do the calculations and convert back.

AM
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top