Determine location of structural break in cross-section data

phantomcow2
Messages
52
Reaction score
0
I'm trying to run a simple regression for a data set (n=165). I've determined via a Chow Test that there exists a structural break somewhere; the same least squares estimate cannot be accurately used to represent the entire range of values the explanatory variable takes on. I've found two very different (.08 and .2) estimates if I break the data down into two catagories: whenexplanatory variable takes values of less than 70000, and where it takes values above 70,000.

However I only took an educated guess to arrive at the 70,000 figure. Is there a more precise, mathematical method available that allows me to determine where the structural break begins to occur?
 
Physics news on Phys.org
phantomcow2 said:
However I only took an educated guess to arrive at the 70,000 figure. Is there a more precise, mathematical method available that allows me to determine where the structural break begins to occur?

Cluster analysis or discriminant analysis may be useful here. The latter is primarily for anticipated or predetermined subsets in the data.http://faculty.chass.ncsu.edu/garson/PA765/cluster.htm
 
Last edited by a moderator:
There is no hard and fast rule -- a rule of thumb is to rank-order the data and try 5%, 10%, 25% and 50%.
 
Namaste & G'day Postulate: A strongly-knit team wins on average over a less knit one Fundamentals: - Two teams face off with 4 players each - A polo team consists of players that each have assigned to them a measure of their ability (called a "Handicap" - 10 is highest, -2 lowest) I attempted to measure close-knitness of a team in terms of standard deviation (SD) of handicaps of the players. Failure: It turns out that, more often than, a team with a higher SD wins. In my language, that...
Hi all, I've been a roulette player for more than 10 years (although I took time off here and there) and it's only now that I'm trying to understand the physics of the game. Basically my strategy in roulette is to divide the wheel roughly into two halves (let's call them A and B). My theory is that in roulette there will invariably be variance. In other words, if A comes up 5 times in a row, B will be due to come up soon. However I have been proven wrong many times, and I have seen some...

Similar threads

Back
Top