Determine mass and acceleration

Thread starter dahatf0
Start date Oct 2, 2006
Tags

Acceleration Mass

AI Thread Summary

To determine the mass and acceleration of the bowling balls, Newton's 2nd law (F=ma) is applied. The first ball, lifted with a force of 82 N, has an acceleration 'a', while the second ball, lifted with 92 N, has an acceleration of '2a'. Since the masses are equal, the equations can be set up to find the mass and acceleration values. The forces acting on each bowling ball include the applied lifting force and gravitational force. Solving these equations reveals the relationship between the forces, mass, and acceleration of the balls.

Oct 2, 2006

dahatf0

A question was posed to me and for the life of me I cannot figure this out.

A bowling ball is lifted with a constant force of 82 N and has an acceleration of a. A second bowling ball is lifted with a constant force of 92 N and has an acceleration of 2a. Find the mass and acceleration of the balls (the masses are assumed to be the same).

Physics news on Phys.org

Oct 2, 2006

Doc Al

Mentor

What does Newton's 2nd law tell you? What forces act on the bowling ball?

Thread 'I've come across another fluid pressure problem I don't understand'

Neglect gravity other than that of water; neglect friction. F1=ρgsh=1000*10*1*(1+4)=50000 N; F1=ρgsh=1000*10*0.1*4=4000 N; F3=50000-4000=46000 N?

View full post »

Thread 'Struggling to understand the concept of this question (ice cube in water optics question)'

TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

View full post »

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

View full post »