Determine the currents in this electrical network

[Edge Of Pain]

Homework Statement

This is quite an easy problem but I'm not sure if I set up my equations correctly, and I want confirmation.

We are given the following circuit:

And our task is to determine the loop currents i_{1}, i_{2}, i_{3}, i_{4}.

Homework Equations

Kirchhoff's first law: sum of currents entering and leaving a loop = 0.
Kirchhoff's second law: sum of electromotive forces = sum of potential difference of loop.
Ohm's law: V = IR.

The Attempt at a Solution

Just apply Kirchoff's laws and Ohm's laws to get the following:

loop 1:
50(i_{1} - i_{2}) + 30(i_{1} - i_{3}) = 120V

loop 2:
50(i_{2} - i_{1}) + 15i_{2} + 10(i_{2} - i_{3}) + 25(i_{2} - i_{4}) = 120V

loop 3:
30(i_{3} - i_{1}) + 10(i_{3} - i_{2}) + 20(i_{3} - i_{4}) + 5i_{3} = 120V

loop 4:
25(i_{4} - i_{2}) + 10i_{4} + 30i_{4} + 15i_{4} + 20(i_{4} - i_{3}) = 120V

I'm not concerned about finding the numerical values, I'm just wondering if I've set these equations up correctly. Are some of these supposed to be -120 volts on the right hand side? If so, how do I determine that?

 

[gneill]

Only one loop has voltage sources in it, and that's Loop 1. So the RHS of all but the first equation should be zero.

Now, you'll want to be a bit careful about the voltage in Loop 1. Note that one lead is labeled +120 V and the other -120 V. How do you think that might come about? Pencil in what the "missing" circuitry might look like.

 

[Edge Of Pain]

Only one loop has voltage sources in it, and that's Loop 1. So the RHS of all but the first equation should be zero.

Now, you'll want to be a bit careful about the voltage in Loop 1. Note that one lead is labeled +120 V and the other -120 V. How do you think that might come about? Pencil in what the "missing" circuitry might look like.

In that case, RHS of all the equations should be 0 except for loop 1 which should be 240V (potential difference). Is that correct?

 

[gneill]

In that case, RHS of all the equations should be 0 except for loop 1 which should be 240V (potential difference). Is that correct?

Yup. Be sure to get its polarity right in your equation.