Determine the linear acceleration of the tip of the rod

AI Thread Summary
To determine the linear acceleration of the tip of a uniform rod pivoting freely about a hinge, the relationship between linear and angular acceleration is utilized, expressed as a = r(α), where r is the distance from the pivot to the tip and α is the angular acceleration. Given that the rod has a length of 1.08m and an angular acceleration of 13.6 rad/s², the linear acceleration at the tip can be calculated. By substituting the values into the equation, the linear acceleration is found to be approximately 14.68 m/s². The discussion emphasizes the importance of understanding the relationship between linear and angular motion in rotational dynamics. This approach provides a clear method for solving similar problems in physics.
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Homework Statement


Determine the linear acceleration of the tip of the rod. Assume that the force of gravity acts at the center of mass of the rod, as shown


Homework Equations


So there is a first part to this problem that i already got
A uniform rod of mass M = 5.02kg and length L = 1.08m can pivot freely (i.e., we ignore friction) about a hinge attached to a wall, as seen in the figure below.The rod is held horizontally and then released. At the moment of release, determine the angular acceleration of the rod. Use units of rad/s^2. So i got the right answer for this and it was 13.6 rad/s^2. i just don't know what to do for the second part

The Attempt at a Solution

 
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Linear acceleration is related to angular acceleration by the eqn. r(\alpha) = a
 
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