Determine the torque of a driver if driven is known

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To determine the torque of a driver wheel with a 6-meter diameter and an expected RPM of 4, the calculations involve two angle drives with ratios of 40:1 and 10:1. The output RPM is calculated to be 1600 RPM at 3,300 Nm on the driven side. As RPM increases by a factor of 400 due to gearing, the torque decreases correspondingly, leading to a driver torque of 1,320,000 Nm without accounting for friction losses. However, considering friction, the actual driving torque will be greater than this calculated value. The discussion highlights the significant impact of gearing on torque and the importance of factoring in losses.
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I have a driver wheel at 6 meters diameter, expected Rpm=4, Torque=?,

Using two angle drives, at ratios of 40:1 and 10:1 inline (in>4rpm x 40=160rpm>out) & (in>160rpm x 10=1600rpm @3,300nm) driven side,

Can somebody please help to determine the required input torque on the the driver side
 
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If the rpm goes up by a factor of 400 due to gearing, the torque must decrease by a factor of 400. Therefore if you somehow measure 3300 nm at the driven end, the torque of the driver is 400*3300 nm. However, this assumes there are no friction losses in the gearing. The driving torque will be greater than 1320000 nm due to the losses.
 
Well that puts my nose out of per-portion, thank you for your reply
 
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