Determine the unit-step response of the discrete-time LTI systems

AI Thread Summary
To determine the unit-step response of the discrete-time LTI system with the impulse response h[n]=(0.9)^{n}e^{j(\pi/2)n}u[n], the initial approach involves convolving the unit step function x[n] = u[n] with h[n]. This leads to the summation expression ∑(0.9)^{k}e^{j(\pi/2)k}u[n-k] from k = -∞ to ∞, which simplifies to ∑(0.9)^{k}e^{j(\pi/2)k} from k = 0 to n. The summation can be evaluated using the formula for a geometric series, but clarification is needed on defining the variable 'a' in the context of the series. The discussion highlights the confusion around starting the calculation and the need for further guidance on the summation process.
Mr.Tibbs
Messages
23
Reaction score
0
Determine the unit-step response of the discrete-time LTI
systems described by the following impulse responses:

h[n]=(0.9)^{n}e^{j(\pi/2)n}u[n]So I am completely confused. . . I don't even know how to start. . . I want to say that I need to do a summation but the more examples and text I look up the more I'm in the dark. . . any help is appreciated.

The only thing I can think to start is you assume

x[n] = u[n]
 
Physics news on Phys.org
How about convolving u[n] with your h[n]?
 
My apologies for taking so long to reply. I was able to talk to my professor and this is what I have now.

\sum(0.9)^{k}e^{j(\pi/2)k}u[n-k] from k = -∞ to ∞.

this turns into

\sum(0.9)^{k}e^{j(\pi/2)k} from k = 0 to n.

using the property of summation :

\sum a^{k} = \frac{1-a^{n+1}}{1-a}

my new snag is what do I define as a?
 
Back
Top