Determine Velocity for Physics Homework Question

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The discussion centers around a physics homework question involving the velocity of a bar rotating about a pivot point. The student calculated the angular velocity as 2.74 rads/s and noted the elastic potential energy as 56.27 J. The kinetic energy equation used is KE = 0.5*IAw^2, leading to a derived expression for kinetic energy in terms of velocity. A key point raised is the relationship between angular velocity (w) and linear velocity (Vb), specifically w = Vb/0.6, which is clarified by noting that the bar's center of mass continues to move even as the left end is momentarily at rest. The discussion emphasizes the importance of understanding the dynamics of motion at the pivot point.
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Homework Statement



I am doing a past paper question, it is shown in the attached JPEG.

I have done part A and got 2.74 rads/s.

and in my notes ( as we done the solution in class) it says the elastic potetntial energy is 56.27 J, then it goes on to say that when the bar hits horizontal, it rotates about A so,

KE = 0.5*IAw^2

so,

KE = 0.5*((1/3)*20*(1.2^2))*(Vb/0.6)^2 = 13.33Vb^2

why is w=Vb/0.6? wouldn't the kinetic energy transform into all elastic potential energy when the bar is horizontal?


Thanks!
 

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dvep said:
why is w=Vb/0.6? wouldn't the kinetic energy transform into all elastic potential energy when the bar is horizontal?
The bar is not necessarily motionless at the point where it hits the bottom. In fact, you could imagine that if the vertical channel were to continue on downward past this point, the bar could continue falling. The left end of the bar is momentarily at rest at this point, but its center is still moving.
 
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