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Homework Statement
I am doing a past paper question, it is shown in the attached JPEG.
I have done part A and got 2.74 rads/s.
and in my notes ( as we done the solution in class) it says the elastic potetntial energy is 56.27 J, then it goes on to say that when the bar hits horizontal, it rotates about A so,
KE = 0.5*IAw^2
so,
KE = 0.5*((1/3)*20*(1.2^2))*(Vb/0.6)^2 = 13.33Vb^2
why is w=Vb/0.6? wouldn't the kinetic energy transform into all elastic potential energy when the bar is horizontal?
Thanks!