Determining an unknown Hydrocarbon X

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The discussion revolves around identifying a gaseous hydrocarbon X with an approximate molecular weight of 57, which reacts with bromine and permanganate. Participants suggest that X could be a butene, with potential structures including 1-butene, 2-butene, and 2-methylprop-1-ene. The key challenge is determining a single product from the reactions with hydrogen bromide and alcoholic sodium hydroxide, indicating no major or minor products. There is confusion regarding the molecular weight, with clarifications that it should be considered as 56 to 58. Ultimately, the focus remains on finding a hydrocarbon that fits the criteria and yields a single alcohol product.
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Homework Statement


A gaseous hydrocarbon X had an approximate molecular weight of 57. It reacted with both bromine and dilute permanganate solutions. Give the structural formula of the only 3 compounds consistent with this information.
X was treated with hydrogen bromide, and the resulting liquid was then boiled with with alcoholic sodium hydroxide solution. Only one compound was formed. Deduce the structure of X, giving your reasoning.

2. The attempt at a solution
Hello all.

I'm having trouble finding a single structure which satisfies all the criteria.

The first pieces of data I'm given is that the molecular weight is a butene of some description (has a MW of 58 and reacts with permanganate and bromine). So hence my three possible structures would be; 1-butene, 2-butene and 2-methylprop-1-ene.

However, I'm finding it hard to distinguish these three with the next pieces of information we're given. I think that with the given processes involved, the result will be an alcohol of some description, however I cannot think of a mechanism which will break the double bond of the product.

I'm assuming, where it says, one product is formed is the key here which I'm guessing means there are no major and minor products involved.
 
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57 is not 58.
 
miniradman said:
The first pieces of data I'm given is that the molecular weight is a butene of some description (has a MW of 58 and reacts with permanganate and bromine).
I think you made a typo in the molecular weight.

miniradman said:
However, I'm finding it hard to distinguish these three with the next pieces of information we're given. I think that with the given processes involved, the result will be an alcohol of some description, however I cannot think of a mechanism which will break the double bond of the product.
Check out http://www.masterorganicchemistry.com/reaction-guide/addition-of-hbr-to-alkenes/

miniradman said:
I'm assuming, where it says, one product is formed is the key here which I'm guessing means there are no major and minor products involved.
Exactly. The reactions shoud result in a single product with no other possibility.
 
Whoops, sorry the MW would be 56. I know that 56 does not equal 57, however I cannot think of a hydrocarbon with a MW of exactly 57.
 
Sorry, missed the error, what I meant was that you should look for a hydrocarbon with exactly given molar mass.

Do you know what degree of unsaturation is? Do you know what it tells about the molecule? Does it require a double or triple bond?
 
Borek said:
Sorry, missed the error, what I meant was that you should look for a hydrocarbon with exactly given molar mass.
But the statement of the problem says "approximate[/color] molecular weight of 57." Personally, I would take that to be in the range 56 to 58.
 
C4H8 is 56.11, I took "approximate" to mean "ignore the part after the decimal point".
 
Borek said:
I took "approximate" to mean "ignore the part after the decimal point".
I guess I'm sloppier than you are :-p
 
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