Determining charge of q and the spring coated with metal?

AI Thread Summary
The discussion revolves around calculating the charge on two metal spheres connected by an insulating spring and the impact of coating the spring with metal. The correct charge calculated is approximately 3.96e-05 C, contrasting with an incorrect attempt of 3.16e-05 C due to a missing factor in the equation. For the second part of the problem, the transition from an insulating to a conducting spring alters the distribution of charges, affecting the spring's length. Participants emphasize the importance of considering how charge interactions change when conductivity is introduced. Understanding these principles is crucial for accurately solving the problem.
Richard Ros
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Homework Statement


Two initially uncharged identical metal spheres, 1 and 2, are connected by an insulating spring (unstretched length L0 = 1.55 m, spring constant k = 30.0 N/m), as shown in the figure.
Charges +q and –q are then placed on the spheres, and the spring contracts to length L = 1.250 m. Recall that the force exerted by a spring is Fs = kΔx, where Δx is the change in the spring's length from its equilibrium length. {Correct Answer: a. 3.96e-05 C, b. 1.55 m}

(a) Determine the charge q. (b) If the spring is coated with metal to make it conducting, what is the new length of the spring?

Homework Equations



1/4πε0 * q1*q2/r^2
f = -kΔx

The Attempt at a Solution


I set fe = fs and got my answer for letter a as 3.16*10^-5 C, which is incorrect from the actual answer. Not sure why it's .8 difference in value. For letter b, I have no idea how to do b.
 

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Your method for a is correct, you just forgot to write the 1/r².

For question b, you just need to think about what happens to the charges. What changes when you go from an insulated spring to a conducting one?
 
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