Determining Coefficient of Friction for a Sliding Toboggan on a Slope

AI Thread Summary
To determine the coefficient of friction for a toboggan sliding down a 15-degree slope at constant velocity, it is essential to analyze the forces acting on the toboggan. The key forces include gravitational force, normal force, and frictional force. A force diagram can help visualize these components, separating them into x (parallel to the slope) and y (perpendicular to the slope) components. Since the toboggan is moving at constant velocity, the net force is zero, indicating that frictional force equals the component of gravitational force down the slope. Understanding these relationships will lead to calculating the coefficient of friction accurately.
RajNijhar
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Homework Statement


A 10.0kg toboggan is sliding down a hill with a slope of 15.0 degrees. If it is maintaining a constant velocity, what is the coefficent of friction?


Homework Equations


Fnet=ma
Fg=mg
Ffkinetic=mewFnormal i think
Ffstatic=mewFN


The Attempt at a Solution


like I am soo lost i don't know where to begin, my teacher said make an x component and a y component but still it doesn't help me :(
 
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RajNijhar said:

Homework Statement


A 10.0kg toboggan is sliding down a hill with a slope of 15.0 degrees. If it is maintaining a constant velocity, what is the coefficent of friction?


Homework Equations


Fnet=ma
Fg=mg
Ffkinetic=mewFnormal i think
Ffstatic=mewFN


The Attempt at a Solution


like I am soo lost i don't know where to begin, my teacher said make an x component and a y component but still it doesn't help me :(

Problems like this almost always start by drawing a force diagram, and thinking about what are all the forces that act on the object. So start by doing that.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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