Determining perpendicular tangent line

Thendi
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Homework Statement


Determine the coordinates of the points on the graph of f(x) = _/'2x+1 where the tangent line is perpendicular to the line 3x+y+4 = 0

_/' -means square root

Homework Equations


f(x) = _/'2x+1
3x+y+4 = 0

The Attempt at a Solution


I made it equal to y
like y= -3x-4...do I have to find the derivative of f(x) = _/'2x+1
Can somebody show me what I am suppose to do next?
or step by step would be fine too.
 
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What does the derivative of f(x) tell you about, the tangent line?
 
Okay, y= -3x- 4 which means it has slope -3. And that tells you than a perpendicular line must have slope 1/3. Where on the curve does the tangent line have slope 1/3?

By the way, just "sqrt(2x+1)" if a far superior notation to "_/'2x+1".
 
I found the derivative of sqrt(2x+1) which is (2x+1)1/2
Where on the curve does the tangent line have slope 1/3?
Do you use the chair rule?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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