Determining phase shift of two frequencies

Click For Summary

Homework Help Overview

The discussion revolves around determining the time it takes for two frequencies, 4,000 Hz and 5,000 Hz, to become completely out of phase after starting in phase at time t=0. The subject area includes wave mechanics and phase relationships in oscillatory motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand the concept of phase shift and its relation to wavelength and radians. Some participants suggest writing the wave equations in terms of cosine functions and relate the phase shift to the difference in frequencies. Others question whether the approach to equate the phase difference to π radians is correct and express uncertainty about the fundamental concepts involved.

Discussion Status

Participants are exploring various interpretations of the phase shift and the mathematical relationships involved. Some guidance has been offered regarding the formulation of wave equations, but there is still a lack of consensus on the underlying principles and the correct approach to the problem.

Contextual Notes

There are indications of confusion regarding the fundamental ideas of wave behavior and phase relationships, as well as a request for additional resources to aid understanding.

teetar
Messages
35
Reaction score
0

Homework Statement


I'm given two frequencies: 4,000 Hz, and 5,000 Hz.
They are completely in-shift at time ##t=0##.
I am to find the time it takes them to get completely out of phase.

Homework Equations



The Attempt at a Solution


I've not gotten waves very well thus far in physics. My teacher said being completely out of phase occurs at a phase shift of one half wavelength, or, at π rads. Where do I start?
 
Physics news on Phys.org
You need to write each wave as ## E(t)=A \, cos(2 \pi f t) ## where ## f ## is the frequency, because ## f=1/T ## where ## T ## is the period (time of one cycle). The number * inside the cos(*) will define the phase of the wave at time t. I've probably already given you more information than we are supposed to, but hopefully you can work it from here.
 
  • Like
Likes   Reactions: teetar
Charles Link said:
You need to write each wave as ## E(t)=A \, cos(2 \pi f t) ## where ## f ## is the frequency, because ## f=1/T ## where ## T ## is the period (time of one cycle). The number * inside the cos(*) will define the phase of the wave at time t. I've probably already given you more information than we are supposed to, but hopefully you can work it from here.
So, is it as simple as saying that the waves are completely out of shift when 10,000πt - 8,000πt = π, meaning that t = 1/2,000? I must be oversimplifying this without fully understanding the fundamental ideas behind it. Am I evaluating the change in the cosine equal to π rads (cos(10,000πt) - cos(8,000πt) = π)? Or am I still missing the obvious answer?
 
teetar said:
So, is it as simple as saying that the waves are completely out of shift when 10,000πt - 8,000πt = π, meaning that t = 1/2,000? I must be oversimplifying this without fully understanding the fundamental ideas behind it. Am I evaluating the change in the cosine equal to π rads (cos(10,000πt) - cos(8,000πt) = π)? Or am I still missing the obvious answer?
You did it correctly and the answer is in seconds (t=.0005 seconds).
 
  • Like
Likes   Reactions: teetar
Charles Link said:
You did it correctly and the answer is in seconds (t=.0005 seconds).
Thanks for the help! I definitely need to spend more time studying waves.

If anyone passes by this thread and knows of any good resources, could you reply to me with them, or PM me them? I looked all over Google trying to answer this question and didn't find many relevant sources.
 
Phase is the total argument of sin or cos which evolves over time.
So if you have x1 = sin(2πf1t) and x2 = sin(2πf2t) then the phases are 2πf1t and 2πf2t and the equation to solve is 2πf1t = 2πf2t + π with f1 > f2.
There are an infinite number of answers but you want to find the shortest time t satisfying the equation.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 1 ·
Replies
1
Views
9K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
5K
Replies
2
Views
2K
Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K