Determining Planck's Constant Using Diffraction Patterns of X-rays and Electrons

AI Thread Summary
The discussion focuses on determining Planck's constant using diffraction patterns from X-rays and electrons, which are found to be identical. The relationship L = h/p is central, where L is the wavelength, h is Planck's constant, and p is momentum. The momentum of electrons is calculated using their energy of 688eV, applying the formula E = (p^2)/2m. Converting the X-ray wavelength of 46.8pm to SI units allows for the calculation of Planck's constant. The identical diffraction patterns imply that both particles share the same wavelength, reinforcing the validity of the calculations.
Steph
Messages
11
Reaction score
0
I'm stuck on the following question:

the diffraction patterns produced when Xrays of wavelength 46.8pm or electrons of energy 688eV are scattered from the same specimen of aluminium are found to be essentially identical. Use this information to determine the value of Planck's constant, h.

I'll let L = wavelength, p = momentum

So far I've calculated the momentum of the electrons using E = (p^2)/2m. I also have converted the Xray wavelength to SI units.

So I know L = h/p thus h = Lp = constant. But I'm not sure what to do from here. Does the fact they have the same diffraction pattern mean that the wavelength of the X-rays is equal to that of the electron beam?

Thanks for any hints you can give me
 
Physics news on Phys.org
Sorry - I've just found the mistakes in my working and have managed to complete the question :blushing:
 
.

To determine Planck's constant using diffraction patterns of X-rays and electrons, we can use the equation L = h/p where L is the wavelength, h is Planck's constant, and p is the momentum. In this case, we have two different particles (X-rays and electrons) with the same diffraction pattern, which suggests that they have the same wavelength.

First, we can calculate the momentum of the electrons using the given energy of 688eV. We know that the kinetic energy of the electrons is given by E = (p^2)/2m, where m is the mass of the electron. Rearranging this equation, we can solve for the momentum p: p = √(2mE).

Next, we can convert the X-ray wavelength of 46.8pm to SI units (meters) and use this value for L in the equation L = h/p. This will give us a value for h, which is the Planck's constant.

However, in order to get a more accurate value for h, it would be best to repeat this experiment with different X-ray wavelengths and electron energies to ensure that the diffraction patterns are still identical. This will help to eliminate any potential errors or inconsistencies in the data.

Overall, the fact that the X-rays and electrons have the same diffraction pattern suggests that they have the same wavelength, which can be used to determine the value of Planck's constant using the equation L = h/p.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top