Determining probability using combinations/permutations (i think)

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The discussion revolves around calculating probabilities related to a student's performance on an exam with 30 questions, where 10 will be selected for the final. For part a, the student calculated the probability of getting all 10 questions right as approximately 0.1087, expressing concern that this seems low given their knowledge of 25 questions. For part b, the focus shifts to determining the probability of getting at least 8 questions correct, suggesting the need to calculate scenarios for getting 9 right and 1 wrong, as well as 8 right and 2 wrong. The conversation emphasizes the importance of understanding combinations and permutations in these calculations. Overall, the student seeks clarification on their approach and further assistance with the second part of the problem.
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Homework Statement


a student has an exam, the teacher gives 30 questions and 10 of the 30 will be on the final exam. if the student knows how to solve 25 of the 30, what is:
a) the probability he will get perfect
b) the probability he will get at least 8 questions right


Homework Equations


permutations and combinations


The Attempt at a Solution


for part a i have:
sample space= 30Choose10= 30045015
to get all 10 questions right, the 10 questions on the exam must be within the 25 he knows how to do- 25choose10= 3268760. to find the probability i did: 3268760/30045015= 0.1087.
i don't think this is right because it seems too low and since he knows most of the questions i would expect the probability to be higher.

for part b: i use the same sample space of 30choose10, but I am stuck on the "at least 8 questions right part"

any help for this would be appreciated
 
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You've got the first one right. Yeah, it seems kind of low, but then he only knows how to solve 'most of them'. And he has to get 10 right in a row. It's not that unreasonable. For the second one what's the probability he gets 9 questions right and 1 wrong and what's the probability he get 8 right and 2 wrong. Then add those two to the probability from the first question.
 
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