Determining Spring Constant After Collision

AI Thread Summary
To determine the spring constant after a collision, the energy conservation principle is applied, equating the gravitational potential energy of the sliding cart to the elastic potential energy stored in the spring. The mass of the cart is 1.2 kg, descending from a height of 1.8 m, while the stationary cart has a mass of 2.0 kg and experiences maximum spring compression of 2.0 cm. The equations used include Em1 = Em2 and mgh = 1/2kx^2. It's crucial to note that at maximum compression, the stationary cart has started moving, meaning not all initial energy is stored in the spring. This understanding is vital for accurately calculating the spring constant.
fdajkffk
Messages
14
Reaction score
0

Homework Statement


1.2 kg cart slides down frictionless ramp from a height of 1.8m and then onto a horizontal surface where it has a head-on elastic collision with a stationary 2.0kg cart cushioned by an ideal Hooke's Law spring. Maximum compression of spring is 2.0 cm
Determine the spring Constant


Homework Equations





The Attempt at a Solution


Em1=Em2
mgh=1/2kx^2
But this did not get me the answer
 
Physics news on Phys.org
fdajkffk said:

Homework Statement


1.2 kg cart slides down frictionless ramp from a height of 1.8m and then onto a horizontal surface where it has a head-on elastic collision with a stationary 2.0kg cart cushioned by an ideal Hooke's Law spring. Maximum compression of spring is 2.0 cm
Determine the spring Constant


Homework Equations





The Attempt at a Solution


Em1=Em2
mgh=1/2kx^2
But this did not get me the answer

Don't forget that when the spring is at maximum compression, the (previously) stationary cart has already begun to move, so only part of the Initial energy of other Cart is stored in the spring.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top