Determining the limits of integration

ahmetbaba
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Homework Statement



Use a triple integral to find the volume of the solid bounded by the graphs of the equations;

z=9-x3 y=2-x2 y=0 z=0, x is equal to or bigger than 0

Homework Equations


The Attempt at a Solution



Well finding the limits for z and y were simple, they are given, however I'm finding trouble finding the upper limit for x.

0\leq z\ leq9-x^3<br /> <br /> 0\leq y\leq2-x^2&lt;br /&gt; &lt;br /&gt; 0\leq x\leq? &lt;br /&gt; &lt;br /&gt; This may be trivial and something really easy, but I don&amp;#039;t know this particular solution. Thanks for the help
 
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ahmetbaba said:

Homework Statement



Use a triple integral to find the volume of the solid bounded by the graphs of the equations;

z=9-x3 y=2-x2 y=0 z=0, x is equal to or bigger than 0


Homework Equations





The Attempt at a Solution



Well finding the limits for z and y were simple, they are given, however I'm finding trouble finding the upper limit for x.
Fixed your LaTeX below. Click on an expression to see what I did.
ahmetbaba said:
0 \leq z \leq 9 - x^3

0 \leq y \leq 2 - x^2

0 \leq x \leq ?

This may be trivial and something really easy, but I don't know this particular solution. Thanks for the help
If you integrate with respect to x last, I believe that the limits on x are 0 and sqrt(2).
 
No, your first post said specifically "x is equal to or bigger than 0".
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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