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Homework Help: Determining the magnitude of the magnetic field acting on a particle

  1. Aug 26, 2012 #1
    1. *Is my solution correct?
    The problem statement, all variables and given/known data

    A positively charged particle of mass 7.2 X 10^-8 kg is travelling due east with a speed of 85 m/s and enters a 0.31T uniform magnetic field. The particle moves through one-quarter of a circle in 2.2 X 10^3 seconds, at which time it leaves the field heading of south. All during the motion the particle moves perpendicular to the magnetic field. a) What is the magnitude of the magnetic force acting of the particle, b) Determine the charge of the particle.


    2. Relevant equations
    speed = distance/time
    r = mv/qB


    3. The attempt at a solution
    a) velocity = distance/time
    = ∏r/2t
    therefore r = v2t/∏
    =0.119m

    F= mv^2/r
    = 4.37 X 10^-3

    b) F = qvB
    q = F/vB
    = 1.66 X 10^-4C
     
  2. jcsd
  3. Aug 26, 2012 #2
    do you mean 2.2*10-3seconds?
     
  4. Aug 26, 2012 #3
    yes time = 2.2*10^-3 seconds
     
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