Determining the Mass of Jupiter Using Io's Orbital Parameters

AI Thread Summary
To determine the mass of Jupiter using Io's orbital parameters, the relevant equations include Kepler's Third Law and the gravitational force equation. The orbital period of Io is 1.77 days, and its orbital radius is 4.22 x 10^5 km. The mass can be calculated using the formula M = 4π²r³/(GT²), where T must be converted to seconds. After applying the correct calculations, the result approximates 1.9 x 10^27 kg, which aligns closely with the accepted mass of Jupiter. Accurate unit conversions and careful application of the formulas are crucial for obtaining the correct result.
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Homework Statement


Io, a satellite of Jupiter has an orbital period of 1.77 days and an orbital
radius of 4.22 x 10^5 km. From this Data determine the mass of Jupiter


Homework Equations


4pie^2/GM
Kepler's Third Law

The Attempt at a Solution


I keep getting turned around. I know the answer but I
keep finding different ways to start
I also used T^2 = Ka^3
But that seems independ of Mass?
Thanks,
Kevin
 
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Husker70 said:

Homework Statement


Io, a satellite of Jupiter has an orbital period of 1.77 days and an orbital
radius of 4.22 x 10^5 km. From this Data determine the mass of Jupiter


Homework Equations


4pie^2/GM
Kepler's Third Law

The Attempt at a Solution


I keep getting turned around. I know the answer but I
keep finding different ways to start
I also used T^2 = Ka^3
But that seems independ of Mass?
Thanks,
Kevin

A generic equation for orbitting bodies that you may want to commit to memory or have handy for some quick calculations is:

T=2\pi a\sqrt{a/GM}.
 
That was nowhere to be found in my book. Thanks...
Should I next find acceleration by taking 1.77 days
and making it 152928s and then find the circumference
to be 2.65 x 10^9 and then velocity is 17338 m/s?
Is this the right direction to go.
Kevin
 
Husker70 said:
That was nowhere to be found in my book. Thanks...
Should I next find acceleration by taking 1.77 days
and making it 152928s and then find the circumference
to be 2.65 x 10^9 and then velocity is 17338 m/s?
Is this the right direction to go.
Kevin

The a given in that equation is the radius. I remember it from long ago, but, if it's not found in your book, don't bother with it. We can derive it from scratch, can't we? ;)

You want to find the mass of the planet, given by the equation \vec{F}=\vec{G}Mm/\vec{R}^2. You know that this system follows uniform circular motion, too: \vec{a}=\vec{v}^2/\vec{r}. And, that period is time, which can be related with displacement and velocity: \vec{x}/\vec{v}=T. Do you agree?
 
I agree
 
Husker70 said:
I agree

Then you can solve for M. :) Let me know what you try.
 
Except how can I use your first equation when I don't know the mass of Io?
 
Husker70 said:
Except how can I use your first equation when I don't know the mass of Io?

Because \vec{f}=m\vec{a} so the small masses cancel. ;)
 
So a = G(M/r^2)
 
  • #10
Husker70 said:
So a = G(M/r^2)

Yup, which is also equal to the quotient between the square of velocity and radius. Just relate the equations, you'll end up with M.
 
  • #11
So I get v^2 = G(M/r)
I'm not sure how to get M =
 
  • #12
Husker70 said:
So I get v^2 = G(M/r)
I'm not sure how to get M =

\vec{v}=2\pi\vec{r}/T...
 
  • #13
I'm just not seeing it sorry
 
  • #14
Husker70 said:
I'm just not seeing it sorry

\frac{4\pi^2\vec{r}^2}{T^2}=\frac{\vec{G}M}{\vec{r}}\rightarrow M=\frac{4\pi^2\vec{r}^3}{\vec{G}}.
 
  • #15
Thanks a lot for the help but using that equation I don't get the right answer for some reason.
Kevin
 
  • #16
asleight said:
\frac{4\pi^2\vec{r}^2}{T^2}=\frac{\vec{G}M}{\vec{r}}\rightarrow M=\frac{4\pi^2\vec{r}^3}{\vec{G}}.

You forgot the T^2 in the formula.
And never mind the vectors. G is not a vector and r^3 is the magnitude cubed and not the vector cubed.

M=4Pi^2 r^3/(G T^2)

I've got about 1.9 x 10^27 and it's very close to the accepted mass of Jupiter.
The period should be in seconds, right?
 
  • #17
asleight's posts are so full of errors, you're better off ignoring them.
 
  • #18
I figured that out. Thanks again. You were a great help.
Talk to you soon.
Kevin
 
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