Diameter 0.8 m height 1.2 m floats in water

AI Thread Summary
The discussion revolves around calculating how far a cone with a diameter of 0.8 m and height of 1.2 m sinks in a liquid with a density of 1360 kg/m^3. Participants are focused on determining the volume of the submerged portion of the cone and applying buoyancy principles. The relationship between the dimensions of the cone and the submerged height is explored through geometric ratios. There is a consensus that the cone will float partially submerged due to the higher density of the liquid compared to water. The conversation emphasizes using ratios to solve for the submerged depth effectively.
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Homework Statement



Given:
diameter 0.8 m
height 1.2 m
floats in water
how far will it sink in a liquid (density =1360 kg/m^3)

Homework Equations



Buoyant force

The Attempt at a Solution



In the attachment
I'm stuck on how to find the volume of the submerged cone in the liquid
please help
 

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You are doing well, so far. Hint 1: Write d (or r, or x) as a function of L.
 


This what I think: since the liquid is more dense than water, then the cone will float a little. From triangle, 0.8 becomes 0.8+y and 0.4 becomes 0.4-y. The ratio and proportion becomes 0.4/1.2 = x/(0.8 + y). Am I correct? or the cone will sink a little?
 
No. Hint 2: 0.4/1.2 = x/L.
 
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