Diameter of a wire with length, resistance and resistivity

AI Thread Summary
The discussion revolves around calculating the diameter of resistance wires used in a car's heated windscreen. The heater requires 180W of power at 12V, resulting in a current of 15A and a resistance of approximately 1 ohm. The heater comprises 200 parallel wires, each 0.70m long, with a resistance of 160 ohms and a resistivity of 6.0x10^-7 ohmic meters. A user requested the equation needed to calculate the wire diameter, leading to a response that provided the formula for resistance in terms of resistivity, length, and cross-sectional area. The interaction highlights the collaborative nature of problem-solving in physics forums.
Elka
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Homework Statement


This question is about the heated front windscreen of a car
The heater consists of resistance wires which are embedded in the glass

A) The power of the heater needs to be 180W for a satisfactory demisting
A car battery of Negligable internal resistance supplies 12V to operate on the heated screen

Calculate the current required to deliver a power of 180W
180/12=15A

Show that the resistance of the heater when operating is about 1ohm
12/15=0.8 ohms, rounded up=1ohm

B) the heater consists of 200 wires inside the glass
These wires are connected in parallel to the 12V supply

Each of the 200 wires has a length of 0.70m and a resistance R(subscript)p of 160 ohms
The material of the wire has resistivity p=6.0x10^-7ohmic metres

Calculate the DIAMETER of the wire

please people, I don't want the answer, can someone just help me out and give me the equation I need to use? I'm terrible at remembering equations I really need the equation, thanks x
 
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Welcome to PF!

Hi Elka! Welcome to PF! :smile:

Resistance = resistivity times length over cross-section area. :wink:
 
Thank you Tiny Tim! Thats great! You've helped me pick up 4 marks definitely and maybe 5! (past papers homeworks) Thank you so much, you're a lifesaver :D
 
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