Estimating Expected Value of a Random Variable X from 129 Rolls of a Dice

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The discussion revolves around estimating the expected value and variance of the sum of outcomes from rolling a single die 129 times, denoted as X. Participants clarify the terminology, emphasizing that "die" refers to one cube, while "dice" refers to multiple. The main concern is how to calculate the expected value E(X) and variance Var(X) for the sum of these rolls. The Chebyshev inequality is mentioned in relation to determining the upper bound for the probability P(X ≤ 12). Overall, the thread highlights confusion over terminology and the need for clearer problem formulation to assist in calculations.
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Pour an ordinary dice 129 times and let X the sum of all indications that it brings.

Let p=P(X<=12)

What is the minimum upper bound for the probability p resulting from inequality of Chebyshev;

Note: The probability density of X is symmetric about the mean value of X


how i can find the fX(x) of the sum of all indications that brings the dice if we roll it 129?
 
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ParisSpart said:
Pour an ordinary dice 129 times and let X the sum of all indications that it brings.

Let p=P(X<=12)

What is the minimum upper bound for the probability p resulting from inequality of Chebyshev;

Note: The probability density of X is symmetric about the mean value of X


how i can find the fX(x) of the sum of all indications that brings the dice if we roll it 129?

The question is unclear. Do you toss a single die 129 times (each time getting a number from 1 to 6), or do you toss a pair of dice 129 times (each time getting a number from 2 to 12)?

Anyway, you need to show your work first before we can help.
 
we toss a dice 129 times, but i can't think how to find the E(X) and Var(X) of this that's why i aksed for help...
i will estimate any sum? from 1 to 129?
 
ParisSpart said:
we toss a dice 129 times, but i can't think how to find the E(X) and Var(X) of this that's why i aksed for help...
i will estimate any sum? from 1 to 129?

You still have not described your problem in meaningful terms: the words "a dice" are contradictory. The "a" means one but the word "dice" means 2 or more. If you toss just one cube with faces numbered 1--6 you are tossing one die (NOT dice); if you toss two such cubes (giving a total from 2--12 in each toss) you are throwing dice = more than one die. So, which do you mean?
 
we toss one dice 129 times not two...
 
ParisSpart said:
we toss one dice 129 times not two...

No, you don't. You toss one die 129 times. You are tossing a DIE, not DICE.
 
yea anyway , how i am going to estimate the expected value of the random variable X which is the sum of all outcomes i am confused
 
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