Did I do this physics problem right?

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The problem involves calculating the coefficient of friction for a box being pushed at constant velocity. Given a mass of 10kg and a pushing force of 25N, the coefficient of friction is derived using the formula F = μN. Since the box moves at a constant velocity, the net force is zero, leading to the equation 98μ = 25. The calculated coefficient of friction is approximately 0.255, confirming the initial calculation of 0.25 is correct. The discussion emphasizes the importance of understanding the relationship between force, mass, and friction in physics problems.
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Its not for homework, I just want to make sure I can do this.

What is the value of the coefficient of friction between the box and the floor?
A man pushes a box with a mass of 10kg at a constant velocity across the floor. he pushes with a constant force of 25N. What is the coefficient of friction value?


F = ukN
uk = F / N
uk = (25) / ((10)(9.8))
uk = 0.25
 
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You will need to know at what rate the box accelerates at in order to find the friction co-efficient.
 
LostConjugate said:
You will need to know at what rate the box accelerates at in order to find the friction co-efficient.

Not for this problem. If the velocity is constant, which the problem stated, then the net force is zero.

So mgcosθμ = 25

98μ = 25

μ = .2551...

so yes you're correct.
 

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