# Dielectric and Parallel Plate Capacitor, the point?

1. Oct 25, 2012

Hi, so I'm having a little trouble understanding why... you would put a dielectric in between a parallel plate capacitor? I know it increases the capacitance but it does so by lowering the potential difference sooo... The charge is still the same, I believe the potential energy also decreases as well. (correct me if any of what I said was wrong, sorry)

So yeah, if I got my thinking straight, what's the point of putting a dielectric in there? Also am I wrong to say increasing the capacitance, here would do nothing... well great?

Thanks

2. Oct 25, 2012

### vk6kro

Putting a solid dielectric in a capacitor increases the capacitance and so reduces the size of a capacitor for a given capacitance.

It also makes construction of the capacitor easier. Somehow, you need to hold the plates of the capacitor apart and this is not easy with an air dielectric.

Air dielectric capacitors are still used for very small capacitors, especially if they are variable capacitance ones for tuning of resonant circuits.
They are not normally made larger than 1000 pF, though. This is 1 nano Farad or 0.000 000 001 Farads. Such a capacitor would be several cubic inches in volume while a capacitor of 1 Farad can be made in about a cubic inch, because it has a solid dielectric. (Well, the dielectric is an oxide coating on the metal electrodes although the capacitor contains a jelly-like substance.)

3. Oct 25, 2012

### Ratch

The capacitance of a parallel plate capacitor is k*ε*A/d, where k is the dielectric constant, ε is the permittivity of free space, A is the plate area, and d is the plate separation. Do you see potential difference in that formula? No? Then the capacitance is invariant with respect to potential difference.

The charge imbalance? That depends on the capacitance and voltage, doesn't it? Q=C*E . The potential energy? That depends on (1/2)*C*E^2 or (1/2)*(Q^2)/C, doesn't it?

Ratch

4. Oct 27, 2012

### MathINTJ

5. Oct 27, 2012