DiffEQ: Determining the largest interval of a solution

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SUMMARY

The discussion focuses on solving the first-order linear differential equation given by cos(x) (dy/dx) + (sin(x))y = 1. The equation is rewritten as (dy/dx) + (tan(x))y = sec(x), with the integrating factor calculated as sec(x). The solution is derived as y = sin(x) + c(cos(x)), where c is a constant. The largest interval for the solution is determined to be (-π/2, π/2), based on the domain of the secant function.

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The question is to determine the solution to the following 1st order linear DE, along with the largest interval the solution is valid on:

cosx \frac{dy}{dx} + (sinx)y=1



Rewriting it shows it to be linear:
\frac{dy}{dx} + (tanx)y = secx

The intergrating factor is: e^{\int{tanx dx}} = e^{-ln|cosx|} = secx

Multiplying both sides of the DE by the integrating factor, and rewriting the LHS as a derivative of the product of the integrating factor and y:
\frac{d}{dx}[(secx)y]= sex^{2}x

(secx)y = tanx+c

y = sinx + c(cosx)

------------------

Now how do I determine the interval?
 
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I'm multiplying both sides of the equation by secx, which has a domain of (-pi/2, pi/2), so that's the interval. Is this reasoning correct?
 

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