Different units while calculating Acceleration of Rotating Objects

AI Thread Summary
The discussion centers on the calculation of acceleration for rotating objects, specifically addressing the units of centripetal and tangential acceleration. It highlights that centripetal acceleration can be derived from either tangential velocity or angular velocity, while tangential acceleration is calculated using radius and angular acceleration. A key point is that radians are dimensionless, meaning they cancel out in calculations, allowing for the combination of different acceleration types despite initial unit discrepancies. The conversation clarifies that when using consistent units, such as converting angular velocity to radians per second, the formulas remain valid. Ultimately, understanding the nature of radians is crucial for accurate calculations in rotational dynamics.
magnetismman
Messages
6
Reaction score
0
Question on Acceleration of Rotating Objects:

The Physics Textbook I have says that the Acceleration of a spinning object is the Pythagorean-theorum result of sides for Centripetal-Acceleration (toward the rotation center) and Tangential-Acceleration (perpendicular to Centripetal-Acceleration in the direction of movement). It seemed pretty straight-forward, until I got to calculating each. According to the book:

Centripetal-Acceleration – ac :
Is either:
(1) Tangential-Velocity squared, over radius OR
(2) Angular-Velocity squared, times radius.

Tangential Acceleration – at :
Radius * Angular-Acceleration.

The problem I think I've found is in the units for each.

For Centripetal-Acceleration:
Tangential-Velocity = radius * angular-velocity (meter-radians-per-second)
Radius is a base unit (meters)
...so Tangential-Velocity squared, over radius has the unit:
(radian-radian-meters-per-second-per-second)
Please note, I did get a “Domain of result may be larger” warning from my calculator.

For Tangential-Acceleration:
Angular-Acceleration = Angular-Velocity-Change per second (Radians-per-second-per-second)
Radius is a base unit (meters)
...so Radius times Angular-Acceleration has the unit:
(radian-meters-per-second-per-second)

How can the two be combined for a total rotational-acceleration if the units are different?

Centripetal-Acceleration (ac): (radians2*meters / second2)
Tangential-Acceleration (at): (radians*meters / second2)


Since the units are different, the combined acceleration would be in neither unit.
Is this a flaw in the theory?
Is this some flaw in my reasoning?
Thank you for your advice.

Information-Source: Cutnell&Johnson - 'Physics' 6th Edition (Chapter 8) – ISBN:0-471-15183-1
 
Last edited:
Physics news on Phys.org
radians aren't physical units. Strictly speaking an angle is defined as an arch (measured in meters) divided by a radius (measured in meters), giving you the identity 1 radian = 1 meter/meter = 1. That means radians are adimensional. That's why the units (meter-radians-per-second) that you obtained for the tangential velocity may also be expressed as the more familiar (meters-per-second).
 
  • Like
Likes 1 person
dauto said:
radians are adimensional.

Thank you. So am I to understand that since a radian is a meter-per-meter, the units cancel evenly? If so, is there any difference implied by the fact that the radians (meters-per-meter) cancel out different numbers of times for 'equivalent' units? Thanks again.
 
magnetismman said:
Thank you. So am I to understand that since a radian is a meter-per-meter, the units cancel evenly?
Yes.
If so, is there any difference implied by the fact that the radians (meters-per-meter) cancel out different numbers of times for 'equivalent' units? Thanks again.
No, no difference.
 
  • Like
Likes 1 person
The important thing about radians here is that they are lexactly "meters per meter". If you measured the angular velocity in degrees per second, or revolutions per minute, you would have an extra factor in the formulas, just like if you measured velocity in miles per hour but distance in meters.

In real life angular velocities are often measured in RPM etc, so you have to convert them to radians/second before using the formulas.
 
  • Like
Likes 1 person
Hi there, im studying nanoscience at the university in Basel. Today I looked at the topic of intertial and non-inertial reference frames and the existence of fictitious forces. I understand that you call forces real in physics if they appear in interplay. Meaning that a force is real when there is the "actio" partner to the "reactio" partner. If this condition is not satisfied the force is not real. I also understand that if you specifically look at non-inertial reference frames you can...
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top