Differentiability on a closed interval

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SUMMARY

The function g(x) = x is differentiable on the closed interval [-π, π]. The derivative g'(a) is calculated using the limit definition of the derivative, resulting in g'(a) = 1 for all a within the interval. This confirms that the function is linear and has a constant slope of 1 across the specified range. Therefore, the conclusion is that g(x) = x is differentiable on [-π, π] with a derivative of 1.

PREREQUISITES
  • Understanding of the limit definition of a derivative
  • Familiarity with basic calculus concepts
  • Knowledge of continuous functions
  • Ability to work with closed intervals in real analysis
NEXT STEPS
  • Study the properties of differentiable functions on closed intervals
  • Learn about the Mean Value Theorem and its applications
  • Explore the implications of differentiability on continuity
  • Investigate higher-order derivatives and their significance
USEFUL FOR

Students studying calculus, educators teaching differentiation, and anyone interested in the properties of linear functions and their derivatives.

Niles
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Homework Statement


Hi all

I wish to show differentiability of g(x)=x on the interval [-pi, pi]. This is what I have done:

<br /> g&#039;(a) = \mathop {\lim }\limits_{h \to 0} \frac{{g\left( {a + h} \right) - g\left( {a} \right)}}{h} \\<br /> = \mathop {\lim }\limits_{h \to 0} \frac{h}{h} \\<br /> = 1,<br />

for a in the interval [-pi,pi]. Hence we see that the derivative is 1 on this interval.

Am I correct?


Niles.
 
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