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Hi all

I wish to show differentiability of g(x)=x on the interval [-pi, pi]. This is what I have done:

[tex]

g'(a) = \mathop {\lim }\limits_{h \to 0} \frac{{g\left( {a + h} \right) - g\left( {a} \right)}}{h} \\

= \mathop {\lim }\limits_{h \to 0} \frac{h}{h} \\

= 1,

[/tex]

forain the interval [-pi,pi]. Hence we see that the derivative is 1 on this interval.

Am I correct?

Best,

Niles.

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# Homework Help: Differentiability on a closed interval

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